differentiation

Question: $\frac{d}{{dx}}{\sin ^{ - 1}}(3x - 4{x^3}) = $



1) $\frac{3}{{\sqrt {1 - {x^2}} }}$
2) $\frac{{ - 3}}{{\sqrt {1 - {x^2}} }}$
3) $\frac{1}{{\sqrt {1 - {x^2}} }}$
4) $\frac{{ - 1}}{{\sqrt {1 - {x^2}} }}$
Solution: Explanation: Explanation
standard-differentiation

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