magnetism

Question: A small bar magnet has a magnetic moment $1.2 A-m^2$. The magnetic field at a distance 0.1 m on its axis will be : ($\mu _o = 4\pi \times 10^{-7} T-m/A$)



1) $1.2 \times 10^{–4}T$
2) $2.4 \times 10^{–4} T$
3) $2.4 \times 10^4 T$
4) $1.2 \times 10^4 T$
Solution: Explanation: No Explanation
Magnet and It's Properties

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