magnetism

Question: A magnetic needle lying parallel to a magnetic field requires W units of work to turn it through 60°. The torque required to maintain the needle in this position will be



1) $\sqrt 3 \,W$
2) W
3) $\frac{{\sqrt 3 }}{2}W$
4) 2W
Solution: Explanation: No Explanation
Magnet and It's Properties

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