differentiation

Question: If $y = x\sin x,$ then



1) $\frac{1}{y}\frac{{dy}}{{dx}} = \frac{1}{x} + \cot x$
2) $\frac{{dy}}{{dx}} = \frac{1}{x} + \cot x$
3) $\frac{1}{y}\frac{{dy}}{{dx}} = \frac{1}{x} - \cot x$
4) None of these
Solution: Explanation: Explanation
standard-differentiation

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