Moving Charges and Magnetism

Question: Two straight parallel wires, both carrying 10 ampere in the same direction attract each other with a force of $1 \times {10^{ - 3}}N$. If both currents are doubled, the force of attraction will be

1) $1 \times {10^{ - 3}}\,N$

2) $2 \times {10^{ - 3}}\,N$

3) $4 \times {10^{ - 3}}\,N$

4) $0.25 \times {10^{ - 3}}\,N$

Solution:

Explanation: No Explanation

Force and Torque on a Current Carrying Conductor

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