Categories > Moving Charges and Magnetism > Motion of Charged Particle In Magnetic Field > Two particles A and B of masses ${m_A}$ and ${m_B}$ respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to this plane. The speeds of the particles are ${v_A}$ and ${v_B}$ respectively, and the trajectories are as shown in the figure. Then

Moving Charges and Magnetism

Question: Two particles A and B of masses ${m_A}$ and ${m_B}$ respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to this plane. The speeds of the particles are ${v_A}$ and ${v_B}$ respectively, and the trajectories are as shown in the figure. Then

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1) ${m_A}{v_A} < {m_B}{v_B}$
2) ${m_A}{v_A} > {m_B}{v_B}$
3) ${m_A} < {m_B}\,\,{\rm{and}}\,\,{v_A} < {v_B}$
4) ${m_A} = \,{m_B}\,{\rm{and }}{v_A} = {v_B}$
Solution: Explanation: No Explanation
Motion of Charged Particle In Magnetic Field

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