Categories > differentiation > standard-differentiation > If $y = 1 + x + \frac{{{x^2}}}{{2!}} + \frac{{{x^3}}}{{3!}} + .....\infty ,$then $\frac{{dy}}{{dx}} = $

differentiation

Question: If $y = 1 + x + \frac{{{x^2}}}{{2!}} + \frac{{{x^3}}}{{3!}} + .....\infty ,$then $\frac{{dy}}{{dx}} = $


1) y
2) $y - 1$
3) $y + 1$
4) None of these
Solution: Explanation: Explanation
standard-differentiation

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