differentiation

Question: If ${x^p}{y^q} = {(x + y)^{p + q}},$then $\frac{{dy}}{{dx}} = $



1) $\frac{y}{x}$
2) $ - \frac{y}{x}$
3) $\frac{x}{y}$
4) $ - \frac{x}{y}$
Solution: Explanation: Explanation
Implicit-function

Rate this question:

Average rating: (0 votes)

Previous Question Next Question