Current Electricity

Question: An electric bulb is designed to draw power P0 at voltage V0. If the voltage is V it draws a power P. Then

1) $P = {\left( {\frac{{{V_0}}}{V}} \right)^2}{P_0}$

2) $P = {\left( {\frac{V}{{{V_0}}}} \right)^2}{P_0}$

3) $P = \left( {\frac{V}{{{V_0}}}} \right)\,{P_0}$

4) $P = \left( {\frac{{{V_0}}}{V}} \right)\,{P_0}$

Solution:

Explanation: No Explanation

Heating Effect of Current Electric Power

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