Current Electricity

Question: We have a galvanometer of resistance $25\,\Omega $. It is shunted by a $2.5\,\Omega $ wire. The part of total current that flows through the galvanometer is given as

1) $\frac{I}{{{I_0}}} = \frac{1}{{11}}$

2) $\frac{I}{{{I_0}}} = \frac{1}{{10}}$

3) $\frac{I}{{{I_0}}} = \frac{3}{{11}}$

4) $\frac{I}{{{I_0}}} = \frac{4}{{11}}$

Solution:

Explanation: No Explanation

Different Measuring Instruments Potentiometer Meter Bridge

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