Questions in vectors

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A particle moves in the x-y plane under the action of a force $\overrightarrow F $ such that the value of its linear momentum $(\overrightarrow P )$ at anytime t is ${P_x} = 2\cos t,\,{p_y} = 2\sin t.$The angle $\theta $between $\overrightarrow F $ and $\overrightarrow P $ at a given time t. will be
The area of the parallelogram represented by the vectors $\overrightarrow A = 2\hat i + 3\hat j$ and $\overrightarrow B = \hat i + 4\hat j$ is
A vector ${\overrightarrow F _1}$is along the positive X-axis. If its vector product with another vector ${\overrightarrow F _2}$is zero then ${\overrightarrow F _2}$ could be
If for two vectors $\overrightarrow A $ and $\overrightarrow B ,\overrightarrow A \times \overrightarrow B = 0,$the vectors
The angle between vectors $(\overrightarrow {\rm{A}} \times \overrightarrow {\rm{B}} )$ and $(\overrightarrow {\rm{B}} \times \overrightarrow {\rm{A}} )$ is
What is the angle between $(\overrightarrow P + \overrightarrow Q )$ and $(\overrightarrow P \times \overrightarrow Q )$
The resultant of the two vectors having magnitude 2 and 3 is 1. What is their cross product
Let $\overrightarrow A = \hat iA\,\cos \theta + \hat jA\,\sin \theta $ be any vector. Another vector $\overrightarrow B $ which is normal to A is
The angle between two vectors given by $6\bar i + 6\bar j - 3\bar k$ and $7\overline i + 4\overline j + 4\overline k $ is
A vector $\overrightarrow A $ points vertically upward and $\overrightarrow B $points towards north. The vector product $\overrightarrow A \times \overrightarrow B $ is

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