Categories > vectors > multiplication-of-vectors > A particle moves in the x-y plane under the action of a force $\overrightarrow F $ such that the value of its linear momentum $(\overrightarrow P )$ at anytime t is ${P_x} = 2\cos t,\,{p_y} = 2\sin t.$The angle $\theta $between $\overrightarrow F $ and $\overrightarrow P $ at a given time t. will be

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Question: A particle moves in the x-y plane under the action of a force $\overrightarrow F $ such that the value of its linear momentum $(\overrightarrow P )$ at anytime t is ${P_x} = 2\cos t,\,{p_y} = 2\sin t.$The angle $\theta $between $\overrightarrow F $ and $\overrightarrow P $ at a given time t. will be


1) $\theta = 0^\circ $
2) $\theta = 30^\circ $
3) $\theta = 90^\circ $
4) $\theta = 180^\circ $
Solution: Explanation: explanation
multiplication-of-vectors

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