Questions in pair-st-lines

Select	Question
	One bisector of the angle between the lines given by $a{{(x-1)}^{2}}+2h\,(x-1)y+b{{y}^{2}}=0$ is $2x+y-2=0$. The other bisector is
	The point of intersection of the lines represented by the equation $2{{x}^{2}}+3{{y}^{2}}+7xy+8x+14y+8=0$ is
	The point of intersection of the lines represented by equation $2{{(x+2)}^{2}}+3(x+2)(y-2)-2{{(y-2)}^{2}}=0$ is
	The lines joining the origin to the points of intersection of the curves $a{{x}^{2}}+2hxy+b{{y}^{2}}+2gx=0$ and $a'{{x}^{2}}+2h'xy+b'{{y}^{2}}+2g'x=0$ will be mutually perpendicular, if
	Distance between the lines represented by the equation ${{x}^{2}}+2\sqrt{3}xy+3{{y}^{2}}-3x-3\sqrt{3}y-4=0$is
	If the lines joining origin to the points of intersection of the line $fx-gy=\lambda $ and the curve ${{x}^{2}}+hxy-{{y}^{2}}+gx+fy=0$ be mutually perpendicular, then
	The equation of the line joining origin to the points of intersection of the curve ${{x}^{2}}+{{y}^{2}}={{a}^{2}}$ and ${{x}^{2}}+{{y}^{2}}-ax-ay=0$ is
	The equation of second degree ${{x}^{2}}+2\sqrt{2}xy+2{{y}^{2}}+4x+4\sqrt{2}y+1=0$ represents a pair of straight lines. The distance between them is
	The equation of pair of straight lines joining the point of intersection of the curve ${{x}^{2}}+{{y}^{2}}=4$ and $y-x=2$ to the origin, is
	The lines joining the points of intersection of line $x+y=1$ and curve ${{x}^{2}}+{{y}^{2}}-2y+\lambda =0$ to the origin are perpendicular, then the value of $1/\sqrt{10}$ will be