pair-st-lines

Question: One bisector of the angle between the lines given by $a{{(x-1)}^{2}}+2h\,(x-1)y+b{{y}^{2}}=0$ is $2x+y-2=0$. The other bisector is



1) $x-2y+1=0$
2) $2x+y-1=0$
3) $x+2y-1=0$
4) $x-2y-1=0$
Solution: Explanation: No Explanation
Bisectors of the angle between the lines Point of intersection of the lines

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