Questions in magnetism

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Two similar bar magnets P and Q, each of magnetic moment M, are taken, If P is cut along its axial line and Q is cut along its equatorial line, all the four pieces obtained have
A magnet of magnetic moment $50\,\hat i\,A{\rm{ - }}{m^2}$ is placed along the x-axis in a magnetic field $\overrightarrow B = (0.5\,\hat i + 3.0\hat j)\,T.$ The torque acting on the magnet is
A bar magnet is held perpendicular to a uniform magnetic field. If the couple acting on the magnet is to be halved by rotating it, then the angle by which it is to be rotated is
There is no couple acting when two bar magnets are placed coaxially separated by a distance because
A bar magnet of magnetic moment $3.0 A-m^2$ is placed in a uniform magnetic induction field of $2 \times 10^{–5} T$. If each pole of the magnet experiences a force of $6 \times 10^{–4} N$, the length of the magnet is
A bar magnet when placed at an angle of $30^o$ to the direction of magnetic field induction of $5 \times 10^{–2} T$, experiences a moment of couple $25 \times 10^{–6} N-m$. If the length of the magnet is 5 cm its pole strength is
Two lines of force due to a bar magnet
The ultimate individual unit of magnetism in any magnet is called
The magnetic field lines due to a bar magnet are correctly shown in Question Image
The magnetic lines of force inside a bar magnet

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