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Two identical short bar magnets, each having magnetic moment of 10 Am2, are arranged such that their axial lines are perpendicular to each other and their centres be along the same straight line in a horizontal plane. If the distance between their centres is 0.2 m, the resultant magnetic induction at a point midway between them is $({\mu _0} = 4\pi \times {10^{ - 7}}H{m^{ - 1}})$
A magnet of length 0.1 m and pole strength ${10^{ - 4}}A.m.$ is kept in a magnetic field of $30\,Wb/{m^2}$ at an angle 30°. The couple acting on it is ……… $ \times {10^{ - 4}}Nm.$
A very small magnet is placed in the magnetic meridian with its south pole pointing north. The null point is obtained 20 cm away from the centre of the magnet. If the earth's magnetic field (horizontal component) at this point be 0.3 gauss, the magnetic moment of the magnet is
Intensity of magnetic field due to earth at a point inside a hollow steel box is
Earth's magnetic field always has a horizontal component except at or Horizontal component of earth's magnetic field remains zero at
A dip needle in a plane perpendicular to magnetic meridian will remain
At magnetic poles of earth, angle of dip is
The correct relation is (Where ${B_H} = $Horizontal component of earth's magnetic field; ${B_V}$= Vertical component of earth's magnetic field and B = Total intensity of earth's magnetic field)
At a certain place, the horizontal component of earth's magnetic field is $\sqrt 3 $times the vertical component. The angle of dip at that place is
The vertical component of earth's magnetic field is zero at or The earth's magnetic field always has a vertical component except at the

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