Questions in indefinite-integration

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$\int_{{}}^{{}}{\frac{x-1}{(x-3)(x-2)}dx=}$
$\int_{{}}^{{}}{\frac{1}{\cos x(1+\cos x)}}\ dx=$
$\int_{{}}^{{}}{\frac{dx}{(x+1)(x+2)}=}$
Correct evaluation of $\int_{{}}^{{}}{\frac{x}{(x-2)(x-1)}\ dx}$ is (where p is an arbitrary constant)
$\int_{{}}^{{}}{\frac{1}{(x-1)({{x}^{2}}+1)}dx}=$
$\int_{{}}^{{}}{\frac{{{x}^{2}}+x-1}{{{x}^{2}}+x-6}\ dx=}$
$\int_{{}}^{{}}{\frac{{{x}^{2}}}{({{x}^{2}}+2)({{x}^{2}}+3)}\ }dx=$
$\int_{{}}^{{}}{\frac{dx}{({{x}^{2}}+1)({{x}^{2}}+4)}=}$
$\int_{{}}^{{}}{\frac{1}{x-{{x}^{3}}}\ dx=}$
If $\int_{{}}^{{}}{\sin 5x\cos 3x\ dx=-\frac{\cos 8x}{16}}+A$, then $A=$

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