indefinite-integration

Question: $\int_{{}}^{{}}{\frac{dx}{({{x}^{2}}+1)({{x}^{2}}+4)}=}$

1) $\frac{1}{3}{{\tan }^{-1}}x-\frac{1}{3}{{\tan }^{-1}}\frac{x}{2}+c$

2) $\frac{1}{3}{{\tan }^{-1}}x+\frac{1}{3}{{\tan }^{-1}}\frac{x}{2}+c$

3) $\frac{1}{3}{{\tan }^{-1}}x-\frac{1}{6}{{\tan }^{-1}}\frac{x}{2}+c$

4) ${{\tan }^{-1}}x-2{{\tan }^{-1}}\frac{x}{2}+c$

Solution:

Explanation: No Explanation

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