Questions in indefinite-integration

Select	Question
	$\int_{{}}^{{}}{\frac{{{e}^{x}}(x-1)}{{{x}^{2}}}\ dx=}$
	$\int_{{}}^{{}}{{{e}^{x}}\left[ \frac{1+x\log x}{x} \right]\ dx=}$
	$\int_{{}}^{{}}{{{e}^{x}}\left[ {{\sin }^{-1}}\frac{x}{a}+\frac{1}{\sqrt{{{a}^{2}}-{{x}^{2}}}} \right]dx=}$
	$\int_{{}}^{{}}{{{e}^{x}}\frac{({{x}^{2}}+1)}{{{(x+1)}^{2}}}dx=}$
	$\int_{{}}^{{}}{{{e}^{x}}\left( \frac{1}{x}-\frac{1}{{{x}^{2}}} \right)}\,dx=$
	$\int{{{e}^{x}}(1+\tan x+{{\tan }^{2}}x)\,\,dx=}$
	$\int{{{e}^{x}}\left( \frac{1-\sin x}{1-\cos x} \right)\,\,dx}$ is equal to
	$\int{\frac{(x+3){{e}^{x}}}{{{(x+4)}^{2}}}\,\,dx=\,\,}$
	$\int{{{\left( \frac{x+2}{x+4} \right)}^{2}}{{e}^{x}}\,\,dx}$ is equal to
	$\int{{{e}^{x}}\left[ f(x)+{f}'(x) \right]\,\,dx}$ is equal to