indefinite-integration

Question: $\int_{{}}^{{}}{\frac{{{e}^{x}}(x-1)}{{{x}^{2}}}\ dx=}$

1) $\frac{1}{x}{{e}^{x}}+c$

2) $x{{e}^{-x}}+c$

3) $\frac{1}{{{x}^{2}}}{{e}^{x}}+c$

4) $\left( x-\frac{1}{x} \right){{e}^{x}}+c$

Solution:

Explanation: No Explanation

Integration by parts

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