Questions in fun-lim

Select	Question
	The value of $\underset{a\to 0}{\mathop{\lim }}\,\frac{\sin a-\tan a}{{{\sin }^{3}}a}$ will be
	$\underset{n\to \infty }{\mathop{\lim }}\,{{\left( \frac{n}{n+y} \right)}^{n}}$ equals
	If $f(x) = \begin{cases} x\;:\;x 0 \end{cases}$, then $\underset{x\to 0}{\mathop{\lim }}\,f(x)=$
	If $f(x) = \begin{cases} \sin x,x \ne n\pi ,n \in Z\\ \,\,\,\,\,\,0,\,\,{\rm{otherwise}} \end{cases}$ and $g(x) = \begin{cases} {x^2} + 1,x \ne 0,\,2\\ \,\,\,\,\,\,\,\,4,x = 0\\ \,\,\,\,\,\,\,\,\,5,x = 2 \end{cases}$ then $\underset{x\to 0}{\mathop{\lim }}\,g\{f(x)\}=$
	$\underset{x\to 1}{\mathop{\lim }}\,\frac{1+\log x-x}{1-2x+{{x}^{2}}}=$
	$\underset{x\to 0}{\mathop{\lim }}\,\frac{{{a}^{\sin x}}-1}{{{b}^{\sin x}}-1}=$
	The value of $\underset{x\to 2}{\mathop{\lim }}\,\frac{{{3}^{x/2}}-3}{{{3}^{x}}-9}$ is
	$\underset{x\to 0}{\mathop{\lim }}\,\frac{{{\sin }^{-1}}x-{{\tan }^{-1}}x}{{{x}^{3}}}$ is equal to
	$\underset{x\to 0}{\mathop{\lim }}\,\frac{x\tan 2x-2x\tan x}{{{(1-\cos 2x)}^{2}}}$ is
	The value of $\underset{x\to 0}{\mathop{\lim }}\,\,\frac{(1-\cos 2x)\sin 5x}{{{x}^{2}}\sin 3x}$ is