Questions in fun-lim

Select	Question
	$\underset{x\to \infty }{\mathop{\lim }}\,{{\left[ 1+\frac{1}{mx} \right]}^{x}}$ equal to
	Let the function f be defined by the equation $f(x) = \begin{cases} 3x\;\;\;\;\;\;{\rm{if}}\;0 \le x \le 1\\ 5 - 3x\;\;{\rm{if}}\;{\rm{1}} < x \le 2 \end{cases}$, then
	The value of the limit of $\frac{{{x}^{3}}-8}{{{x}^{2}}-4}$ as x tends to 2 is
	The value of the limit of $\frac{{{x}^{3}}-{{x}^{2}}-18}{x-3}$ as x tends to 3 is
	$\underset{x\to 0}{\mathop{\lim }}\,\frac{{{\tan }^{-1}}x}{x}$ is
	$x=1$ is equal to
	$\underset{x\to 0}{\mathop{\lim }}\,\sin \left( \frac{1}{x} \right)$ is
	$\underset{x\to 4}{\mathop{\lim }}\,\left[ \frac{{{x}^{3/2}}-8}{x-4} \right]=$
	$\underset{x\to 0}{\mathop{\lim }}\,\frac{{{e}^{\frac{1}{x}}}}{{{e}^{\left( \frac{1}{x}+1 \right)}}}=$
	The value of $\underset{x\to 0}{\mathop{\lim }}\,\frac{x\cos x-\log (1+x)}{{{x}^{2}}}$ is