Questions in electrostatics

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A charged particle of mass $m$and charge $q$is released from rest in a uniform electric field $E$ Neglecting the effect of gravity, the kinetic energy of the charged particle after ‘t’ second is
A proton is about 1840 times heavier than an electron. When it is accelerated by a potential difference of 1 kV, its kinetic energy will be
A conducting sphere of radius $R = 20$ cm is given a charge $Q = 16\mu C$. What is $\overrightarrow E $ at centre
A thin spherical conducting shell of radius $R$ has a charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point p a distance $\frac{R}{2}$ from the centre of the shell is
A hollow conducting sphere is placed in an electric field produced by a point charge placed at P as shown in figure. Let ${V_A},{V_B},{V_C}$ be the potentials at points $A,B$ and C respectively. Then
A point charge is kept at the centre of a metallic insulated spherical shell. Then
An electron moving with the speed $5 \times {10^6}$ per sec is shooted parallel to the electric field of intensity $1 \times {10^3}N/C$. Field is responsible for the retardation of motion of electron. Now evaluate the distance travelled by the electron before coming to rest for an instant (mass of $e = 9 \times {10^{ - 31}}Kg.$ charge $= 1.6 \times {10^{ - 19}}C)$
An electron enters in high potential region ${V_2}$ from lower potential region ${V_1}$ then its velocity
The electric potential at the surface of an atomic nucleus (Z = 50) of radius $ 9.0 \times {10^{ - 13}}$ cm is
A pellet carrying charge of 0.5 coulombs is accelerated through a potential of 2,000 volts. It attains a kinetic energy equal to

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