Questions in differentiation

Select	Question
	If $y = \sin (\sqrt {\sin x + \cos x} )$, then $\frac{{dy}}{{dx}} = $
	If $y = \sin \left( {\frac{{1 + {x^2}}}{{1 - {x^2}}}} \right)$, then $\frac{{dy}}{{dx}} = $
	If $y = \sqrt {\frac{{1 + \tan x}}{{1 - \tan x}}} $, then $\frac{{dy}}{{dx}} = $
	$\frac{d}{{dx}}{({x^2} + \cos x)^4} = $
	$\frac{d}{{dx}}\sqrt {x\sin x} = $
	$\frac{d}{{dx}}\sqrt {{{\sec }^2}x + {\rm{cose}}{{\rm{c}}^2}x} = $
	$\frac{d}{{dx}}\left( {\frac{{\sec x + \tan x}}{{\sec x - \tan x}}} \right) = $
	$\frac{d}{{dx}}\left( {{x^3}{{\tan }^2}\frac{x}{2}} \right)$=
	If $y = {\tan ^{ - 1}}\left( {\frac{{{x^{1/3}} + {a^{1/3}}}}{{1 - {x^{1/3}}{a^{1/3}}}}} \right)$ , then $\frac{{dy}}{{dx}} = $
	If $y = {\cot ^{ - 1}}\left( {\frac{{1 + x}}{{1 - x}}} \right)$, then $\frac{{dy}}{{dx}} = $