Questions in differentiation

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If $y = \frac{{\sqrt x {{(2x + 3)}^2}}}{{\sqrt {x + 1} }},$then $\frac{{dy}}{{dx}} = $
$\frac{d}{{dx}}\{ {(\sin x)^{\log x}}\} = $
If $y = {(\tan x)^{\cot x}}$, then $\frac{{dy}}{{dx}}\backslash $=
If $y = {x^2} + {x^{\log x}},$then $\frac{{dy}}{{dx}} = $
If $y = {x^2} + \frac{1}{{{x^2} + \frac{1}{{{x^2} + \frac{1}{{{x^2} + ......\infty }}}}}},$then $\frac{{dy}}{{dx}} = $
If $y = {\sqrt x ^{{{\sqrt x }^{\sqrt x ....\infty }}}}$, then $\frac{{dy}}{{dx}} = $
If ${x^y}.{y^x} = 1$, then $\frac{{dy}}{{dx}}$=
$y = {(\tan x)^{{{(\tan x)}^{\tan x}}}},$ then at$x = \frac{\pi }{4}$, the value of $\frac{{dy}}{{dx}} = $
If $y = {(\sin x)^{\tan x}}$, then $\frac{{dy}}{{dx}}$is equal to
If $y = {2^{1/{{\log }_x}4}}$, then x is equal to

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