differentiation

Question: If $y = {(\sin x)^{\tan x}}$, then $\frac{{dy}}{{dx}}$is equal to

1) ${(\sin x)^{\tan x}}.(1 + {\sec ^2}x.\log \sin x)$

2) $\tan x.{(\sin x)^{\tan x - 1}}.\cos x$

3) ${(\sin x)^{\tan x}}.{\sec ^2}x.\log \sin x$

4) $\tan x.{(\sin x)^{\tan x - 1}}$

Solution:

Explanation: Explanation

Implicit-function

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