Questions in definite-integral

Select	Question
	$\int_{0}^{\pi /4}{{{\tan }^{6}}x{{\sec }^{2}}x\,dx=}$
	$\int_{0}^{2}{\frac{{{x}^{3}}\,dx}{{{({{x}^{2}}+1)}^{\frac{3}{2}}}}}=$
	$\int_{0}^{\pi /6}{\frac{\sin x}{{{\cos }^{3}}x}\,dx=}$
	$\int_{0}^{\pi /2}{\frac{\sin x\cos x\,dx}{{{\cos }^{2}}x+3\cos x+2}}=$
	The value of the integral $\int_{0}^{\log 5}{\frac{{{e}^{x}}\sqrt{{{e}^{x}}-1}}{{{e}^{x}}+3}}\,dx=$
	The value of the definite integral $\int_{0}^{1}{\frac{dx}{{{x}^{2}}+2x\cos \alpha +1}}$ for $0<\alpha <\pi $ is equal to
	The value of the integral $\int_{-\pi }^{\pi }{\sin mx\sin nx\,dx}$ for $m\ne n$ $(m,\,\,n\in I),$ is
	The greater of $\int_{0}^{\pi /2}{\frac{\sin x}{x}\,dx}$ and $\frac{\pi }{2},$ is
	The integral $\int_{-1}^{3}{\left( {{\tan }^{-1}}\frac{x}{{{x}^{2}}+1}+{{\tan }^{-1}}\frac{{{x}^{2}}+1}{x} \right)}\,dx=$
	If ${{I}_{1}}=\int_{e}^{{{e}^{2}}}{\frac{dx}{\log x}}$ and ${{I}_{2}}=\int_{1}^{2}{\frac{{{e}^{x}}}{x}\,dx,}$ then