Questions in definite-integral

Select	Question
	The value of $\int_{-2}^{3}{\|1-{{x}^{2}}\|dx}$is
	If $f(x)=\|x-1\|$, then $\int_{0}^{2}{f(x)dx}$is
	If $\int_{0}^{\pi }{xf(\sin x)dx=A}\int_{0}^{\pi /2}{f(\sin x)dx}$, then A is
	$\int_{0}^{\pi /2}{{}}(\sin x-\cos x)\log (\sin x+\cos x)\,dx=$
	The function $L(x)=\int_{1}^{x}{\frac{dt}{t}}$ satisfies the equation
	The value of integral $\int_{0}^{1}{{{e}^{{{x}^{2}}}}}dx$ lies in interval
	If $P=\int_{0}^{3\pi }{f({{\cos }^{2}}x)dx}\,\,\text{and}\,\,Q=\int_{0}^{\pi }{f({{\cos }^{2}}x)dx}$, then
	Let $a,\,\,b,\,\,c$ be non-zero real numbers such that $\int_{0}^{3}{(3a{{x}^{2}}+2bx+c)\,dx}=\int_{1}^{3}{(3a{{x}^{2}}+2bx+c})\,dx\,,$ then
	$\int_{-\pi }^{\pi }{{{(\cos px-\sin qx)}^{2}}dx}$ is equal to (where $p$ and $q$ are integers)
	If $g(x)=\int_{0}^{x}{{{\cos }^{4}}t\,dt,}$ then $g(x+\pi )$ equals