Questions in circle

Select	Question
	The point of contact of the given circles ${{x}^{2}}+{{y}^{2}}-6x-6y+10=0$ and ${{x}^{2}}+{{y}^{2}}=2$ , is
	From three non- collinear points we can draw
	The point (2, 3) is a limiting point of a coaxial system of circles of which ${{x}^{2}}+{{y}^{2}}=9$ is a member. The co-ordinates of the other limiting point is given by
	The equation of the circle having its centre on the line $x+2y-3=0$ and passing through the points of intersection of the circles ${{x}^{2}}+{{y}^{2}}-2x-4y+1=0$ and ${{x}^{2}}+{{y}^{2}}-4x-2y+4=0$ , is
	If a circle passes through the point (1, 2) and cuts the circle ${{x}^{2}}+{{y}^{2}}=4$ orthogonally, then the equation of the locus of its centre is
	Circles ${{x}^{2}}+{{y}^{2}}-2x-4y=0$ and ${{x}^{2}}+{{y}^{2}}-8y-4=0$
	The two circles ${{x}^{2}}+{{y}^{2}}-4y=0$ and ${{x}^{2}}+{{y}^{2}}-8y=0$
	The equation of a circle passing through points of intersection of the circles ${{x}^{2}}+{{y}^{2}}+13x-3y=0$ and $2{{x}^{2}}+2{{y}^{2}}+4x-7y-25=0$ and point (1, 1) is
	The locus of centre of a circle passing through (a, b) and cuts orthogonally to circle ${{x}^{2}}+{{y}^{2}}={{p}^{2}}$ , is
	The equation of the circle which intersects circles ${{x}^{2}}+{{y}^{2}}+x+2y+3=0$ ,${{x}^{2}}+{{y}^{2}}+2x+4y+5=0$ and ${{x}^{2}}+{{y}^{2}}-7x-8y-9=0$ at right angle, will be