circle

Question: The point of contact of the given circles ${{x}^{2}}+{{y}^{2}}-6x-6y+10=0$ and ${{x}^{2}}+{{y}^{2}}=2$ , is



1) (0, 0)
2) (1, 1)
3) (1, –1)
4) (–1, –1)
Solution: Explanation: No Explanation
System of circles

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