Questions in Units and Measurements

SelectQuestion
Accuracy of measurement is determined by
The radius of a sphere is ($5.3 \pm 0.1$) cm. The percentage error in its volume is
A thin copper wire of length l metre increases in length by 2% when heated through 10ºC. What is the percentage increase in area when a square copper sheet of length l metre is heated through 10ºC
In the context of accuracy of measurement and significant figures in expressing results of experiment, which of the following is/are correct (1) Out of the two measurements 50.14 cm and 0.00025 ampere, the first one has greater accuracy (2) If one travels 478 km by rail and 397 m. by road, the total distance travelled is 478 km.
A physical parameter a can be determined by measuring the parameters b, c, d and e using the relation a = ${b^\alpha }{c^\beta }/{d^\gamma }{e^\delta }$. If the maximum errors in the measurement of b, c, d and e are ${b_1}$%, ${c_1}$%, ${d_1}$% and ${e_1}$%, then the maximum error in the value of a determined by the experiment is
The relative density of material of a body is found by weighing it first in air and then in water. If the weight in air is (5.00$ \pm 0.05$) Newton and weight in water is (4.00$ \pm $0.05) Newton. Then the relative density along with the maximum permissible percentage error is
The resistance R =$\frac{V}{i}$ where V= 100 $ \pm $5 volts and i = 10 $ \pm $0.2 amperes. What is the total error in R
The period of oscillation of a simple pendulum in the experiment is recorded as 2.63 s, 2.56 s, 2.42 s, 2.71 s and 2.80 s respectively. The average absolute error is
The length of a cylinder is measured with a meter rod having least count 0.1 cm. Its diameter is measured with vernier callipers having least count 0.01 cm. Given that length is 5.0 cm. and radius is 2.0 cm. The percentage error in the calculated value of the volume will be
In an experiment, the following observation's were recorded : L = 2.820 m, M = 3.00 kg, l = 0.087 cm, Diameter D = 0.041 cm Taking g = 9.81 $m/{s^2}$using the formula , Y=$\frac{{4MgL}}{{\pi {D^2}l}}$, the maximum permissible error in Y is

View Selected Questions (0)

Back to Categories

Back to Home