Units and Measurements

Question: The radius of a sphere is ($5.3 \pm 0.1$) cm. The percentage error in its volume is



1) $\frac{{0.1}}{{5.3}} \times 100$
2) $3 \times \frac{{0.1}}{{5.3}} \times 100$
3) $\frac{{0.1 \times 100}}{{3.53}}$
4) $3 + \frac{{0.1}}{{5.3}} \times 100$
Solution: Explanation: explanation
Errors-in-Measurement

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