Questions in Oscillations

Select	Question
	The displacement of a particle in S.H.M. is indicated by equation $y = 10 \sin(20t + \pi /3)$ where $y$ is in meters. The value of maximum velocity of the particle will be:
	The displacement of a particle in S.H.M. is indicated by equation $y = 10 \sin(20t + \pi /3)$ where $y$ is in meters. The value of phase constant will be :
	The phase of a particle in SHM at time $t$ is $\frac{\pi}{6}$. The following inference is drawn from this:
	The value of phase at maximum distance from the mean position of a particle in S.H.M. is:
	Two particles execute S.H.M. along the same line at the same frequency. They move in opposite direction at the mean position. The phase difference will be:
	The time period of an oscillator is 8 sec. The phase difference from $t = 2 sec$ to $t = 4 sec$ will be:
	The displacement from mean position of a particle in SHM at 3 seconds is \[\sqrt 3 /2\] of the amplitude. Its time period will be:
	A particle executes SHM of type $x = a\sin \omega t$. It takes time $t_1$ from $x = 0$ to $x = \frac{a}{2}$ and $t_2$ from $x = \frac{a}{2}$ to $x = a$. The ratio of $t_1 : t_2$ will be:
	The time taken by a particle in SHM for maximum displacement is:
	A particle executes SHM with periodic time of 6 seconds. The time taken for traversing a distance of half the amplitude from mean position is: