Questions in Oscillations

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	Two masses $m_1$ and $m_2$ are suspended together by a massless spring of constant $K$. When the masses are in equilibrium, $m_1$ is removed without disturbing the system. The amplitude of oscillations is
	A spring executes SHM with mass of 10kg attached to it. The force constant of spring is 10N/m.If at any instant its velocity is 40cm/sec, the displacement will be (where amplitude is 0.5m)
	The acceleration of a particle executing S.H.M. is
	A particle executing S.H.M. completes a distance (taking friction as negligible) in one complete time period, equal to:
	A particle of mass $m$ is executing S.H.M. If amplitude is $a$ and frequency $n$, the value of its force constant will be:
	The mass of particle executing S.H.M. is 1 gm. If its periodic time is $\pi$ seconds, the value of force constant is:
	The equation of motion of a particle executing S.H.M. is :
	The equation of motion of a particle executing SHM is \[\left( {\frac{{{d^2}x}}{{d{t^2}}}} \right) + kx = 0\]. The time period of the particle will be:
	The phase of a particle in S.H.M. is \[\frac{\pi}{2}\], then:
	The displacement of a particle in S.H.M. is indicated by equation $y = 10 \sin(20t + \pi /3)$ where $y$ is in meters. The value of time period of vibration will be (in seconds):