Questions in Oscillations

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	The mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum on this planet will be (If it is a second's pendulum on earth)
	A simple pendulum is set up in a trolley which moves to the right with an acceleration a on a horizontal plane. Then the thread of the pendulum in the mean position makes an angle $\theta $ with the vertical
	Which of the following statements is not true ? In the case of a simple pendulum for small amplitudes the period of oscillation is
	The time period of a second's pendulum is 2 sec. The spherical bob which is empty from inside has a mass of 50 gm. This is now replaced by another solid bob of same radius but having different mass of 100 gm. The new time period will be
	A man measures the period of a simple pendulum inside a stationary lift and finds it to be $T$ sec. If the lift accelerates upwards with an acceleration $g/4$, then the period of the pendulum will be
	A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration $a$, then the time period is given by $T=2\pi \sqrt{\frac{l}{{{g}'}}}$, where ${g}'$ is equal to
	A second's pendulum is placed in a space laboratory orbiting around the earth at a height $3R$, where $R$ is the radius of the earth. The time period of the pendulum is
	The bob of a simple pendulum of mass $m$ and total energy $E$ will have maximum linear momentum equal to
	The length of the second pendulum on the surface of earth is 1 m. The length of seconds pendulum on the surface of moon, where g is 1/6th value of g on the surface of earth, is
	If the length of second's pendulum is decreased by 2%, how many seconds it will lose per day

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