Questions in Oscillations

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	A particle in SHM is described by the displacement equation $x(t)=A\cos (\omega t + \theta )$. If the initial ($t = 0$) position of the particle is 1 cm and its initial velocity is $\pi $cm/s, what is its amplitude? The angular frequency of the particle is $\pi {{s}^{-1}}$
	A particle executes SHM in a line 4 cm long. Its velocity when passing through the centre of line is 12 cm/s. The period will be
	The displacement x (in metre) of a particle in, simple harmonic motion is related to time t (in seconds) as $x=0.01\cos \left( \pi \,t+\frac{\pi }{4} \right)$. The frequency of the motion will be
	A simple harmonic wave having an amplitude $a$ and time period $T$ is represented by the equation $y=5\sin \pi (t+4)m.$Then the value of amplitude ($a$) in ($m$) and time period ($T$) in second are
	A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is
	The displacement x (in metres) of a particle performing simple harmonic motion is related to time t (in seconds) as $x=0.05\cos \left( 4\,\pi \,t+\frac{\pi }{4} \right)$. The frequency of the motion will be
	The period of a simple pendulum is doubled, when
	The period of oscillation of a simple pendulum of constant length at earth surface is T. Its period inside a mine is
	A simple pendulum is made of a body which is a hollow sphere containing mercury suspended by means of a wire. If a little mercury is drained off, the period of pendulum will
	A pendulum suspended from the ceiling of a train has a period T, when the train is at rest. When the train is accelerating with a uniform acceleration a, the period of oscillation will

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