Questions in Moving Charges and Magnetism

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A proton of mass m and charge +e is moving in a circular orbit in a magnetic field with energy 1 MeV. What should be the energy of $\alpha - $particle (mass = 4m and charge = + 2e), so that it can revolve in the path of same radius
An electron is moving with a speed of ${10^8}\,m/\sec $ perpendicular to a uniform magnetic field of intensity B. Suddenly intensity of the magnetic field is reduced to B/2. The radius of the path becomes from the original value of r
A proton and an $\alpha - $particle enter a uniform magnetic field perpendicularly with the same speed. If proton takes 25 $\mu $ sec to make 5 revolutions, then the periodic time for the $\alpha - $particle would be
A proton (mass $ = 1.67 \times {10^{ - 27}}\,kg$ and charge $ = 1.6 \times {10^{ - 19}}\,C)$ enters perpendicular to a magnetic field of intensity 2 $weber/{m^2}$ with a velocity $3.4 \times {10^7}\,m/\sec $. The acceleration of the proton should be
An $\alpha - $particle travels in a circular path of radius 0.45 m in a magnetic field $B = 1.2\,Wb/{m^2}$ with a speed of $2.6 \times {10^7}\,m/\sec $. The period of revolution of the $\alpha - $particle is
A uniform magnetic field B is acting from south to north and is of magnitude 1.5 $Wb/{m^2}$. If a proton having mass $ = 1.7 \times {10^{ - 27}}\,kg$ and charge $ = 1.6 \times {10^{ - 19}}\,C$ moves in this field vertically downwards with energy 5 MeV, then the force acting on it will be
A strong magnetic field is applied on a stationary electron, then
A uniform magnetic field acts at right angles to the direction of motion of electrons. As a result, the electron moves in a circular path of radius 2 cm. If the speed of the electrons is doubled, then the radius of the circular path will be
A deutron of kinetic energy 50 keV is describing a circular orbit of radius 0.5 metre in a plane perpendicular to magnetic field $\overrightarrow B $. The kinetic energy of the proton that describes a circular orbit of radius 0.5 metre in the same plane with the same $\overrightarrow B $ is
If a proton is projected in a direction perpendicular to a uniform magnetic field with velocity v and an electron is projected along the lines of force, what will happen to proton and electron

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