Moving Charges and Magnetism

Question: A uniform magnetic field B is acting from south to north and is of magnitude 1.5 $Wb/{m^2}$. If a proton having mass $ = 1.7 \times {10^{ - 27}}\,kg$ and charge $ = 1.6 \times {10^{ - 19}}\,C$ moves in this field vertically downwards with energy 5 MeV, then the force acting on it will be



1) $7.4 \times {10^{12}}\,N$
2) $7.4 \times {10^{ - 12}}\,N$
3) $7.4 \times {10^{19}}\,N$
4) $7.4 \times {10^{ - 19}}\,N$
Solution: Explanation: No Explanation
Motion of Charged Particle In Magnetic Field

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