Questions in Gravitation

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For the moon to cease to remain the earth's satellite, its orbital velocity has to increase by a factor of
The escape velocity of an object from the earth depends upon the mass of the earth (M), its mean density $(\rho )$, its radius (R) and the gravitational constant (G). Thus the formula for escape velocity is
Escape velocity on a planet is ${v_e}$. If radius of the planet remains same and mass becomes 4 times, the escape velocity becomes
The mass of the earth is 81 times that of the moon and the radius of the earth is 3.5 times that of the moon. The ratio of the escape velocity on the surface of earth to that on the surface of moon will be
The escape velocity from the surface of earth is ${V_e}$. The escape velocity from the surface of a planet whose mass and radius are 3 times those of the earth will be
How much energy will be necessary for making a body of 500 kg escape from the earth $[g = 9.8\,m/{s^2}$, radius of earth $ = 6.4 \times {10^6}\,m]$
The escape velocity for the earth is 11.2 km/sec. The mass of another planet is 100 times that of the earth and its radius is 4 times that of the earth. The escape velocity for this planet will be
The escape velocity of a planet having mass 6 times and radius 2 times as that of earth is
The escape velocity of an object on a planet whose g value is 9 times on earth and whose radius is 4 times that of earth in km/s is
The escape velocity on earth is 11.2 km/s. On another planet having twice radius and 8 times mass of the earth, the escape velocity will be

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