Gravitation

Question: The escape velocity of an object from the earth depends upon the mass of the earth (M), its mean density $(\rho )$, its radius (R) and the gravitational constant (G). Thus the formula for escape velocity is

1) $v = R\sqrt {\frac{{8\pi }}{3}G\rho }$

2) $v = M\sqrt {\frac{{8\pi }}{3}GR}$

3) $v = \sqrt {2GMR}$

4) $v = \sqrt {\frac{{2GM}}{{{R^2}}}}$

Solution:

Explanation: No Explanation

Gravitation Potential Gravitational Potential Energy and Escape Velocity

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