Questions in Electrostatics

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The electric potential $V$ is given as a function of distance $x$ (metre) by $V = (5{x^2} + 10x - 9)\,volt$. Value of electric field at $x = 1$ is
Two metal pieces having a potential difference of $800\,V$ are $0.02\,m$ apart horizontally. A particle of mass $1.96 \times {10^{ - 15}}kg$ is suspended in equilibrium between the plates. If $e$ is the elementary charge, then charge on the particle is
The figure shows some of the electric field lines corresponding to an electric field. The figure suggests
Two spheres of radius $a$ and $b$ respectively are charged and joined by a wire. The ratio of electric field of the spheres is
A particle of mass $m$ and charge $q$ is placed at rest in a uniform electric field $E$ and then released. The kinetic energy attained by the particle after moving a distance $y$ is
A hollow insulated conducting sphere is given a positive charge of $10\,\mu \,C$. What will be the electric field at the centre of the sphere if its radius is 2 meters
An electron of mass ${m_e}$ initially at rest moves through a certain distance in a uniform electric field in time ${t_1}$. A proton of mass ${m_p}$ also initially at rest takes time ${t_2}$ to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio of ${t_2}/{t_1}$ is nearly equal to
A cube of side $b$ has a charge $q$ at each of its vertices. The electric field due to this charge distribution at the centre of this cube will be
A charged water drop whose radius is $0.1\,\mu m$ is in equilibrium in an electric field. If charge on it is equal to charge of an electron, then intensity of electric field will be $(g = 10\,m{s^{ - 1}})$
Four charges are placed on corners of a square as shown in figure having side of $5\,cm$. If Q is one microcoulomb, then electric field intensity at centre will be

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