Questions in 3-d

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The equation of the plane which bisects the line joining the points (–1, 2, 3) and (3, –5, 6) at right angle, is
The line$\frac{x-2}{3}=\frac{y-3}{4}=\frac{z-4}{5}$is parallel to the plane
The point where the line $\frac{x-1}{2}=\frac{y-2}{-3}=\frac{z+3}{4}$ meets the plane $2x+4y-z=1$, is
The distance of the point (–1, –5, –10) from the point of intersection of the line $\frac{x-2}{3}=\frac{y+1}{4}=\frac{z-2}{12}$ and the plane $x-y+z=5$, is
The equation of the line passing through (1, 2, 3) and parallel to the planes $x-y+2z=5$ and $3x+y+z=6$, is
The line drawn from (4, –1, 2) to the point (–3, 2, 3) meets a plane at right angles at the point (–10, 5, 4), then the equation of plane is
The ratio in which the line joining the points (a, b, c) and (–a, –c, –b) is divided by the xy-plane is
The line $\frac{x+3}{3}=\frac{y-2}{-2}=\frac{z+1}{1}$ and the plane $4x+5y+3z-5=0$ intersect at a point
If line $\frac{x-{{x}_{1}}}{l}=\frac{y-{{y}_{1}}}{m}=\frac{z-{{z}_{1}}}{n}$ is parallel to the plane $ax+by+cz+d=0$, then
The equation of plane through the line of intersection of planes $ax+by+cz+d=0$, $a'x+b'y+c'z+d'=0$ and parallel to the line $y=0,z=0$ is

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