3-d

Question: The equation of the line passing through (1, 2, 3) and parallel to the planes $x-y+2z=5$ and $3x+y+z=6$, is



1) $\frac{x-1}{-3}=\frac{y-2}{5}=\frac{z-3}{4}$
2) $\frac{x-1}{-3}=\frac{y-2}{-5}=\frac{z-1}{4}$
3) $\frac{x-1}{-3}=\frac{y-2}{-5}=\frac{z-1}{-4}$
4) None of these
Solution: Explanation: No Explanation
Line and plane

Rate this question:

Average rating: (0 votes)

Previous Question Next Question