Current Electricity

Question: Two sources of equal emf are connected to an external resistance R. The internal resistances of the two sources are ${R_1}$ and ${R_2}\,({R_2} > {R_1})$. If the potential difference across the source having internal resistance ${R_2}$ is zero, then



1) $R = {R_1}{R_2}/({R_1} + {R_2})$
2) $R = {R_1}{R_2}/({R_2} - {R_1})$
3) $R = {R_2} \times ({R_1} + {R_2})/({R_2} - {R_1})$
4) $R = {R_2} - {R_1}$
Solution: Explanation: No Explanation
Kirchhoff's Law Cells Internal Resistance

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