Electrostatics

Question: Two thin wire rings each having a radius R are placed at a distance d apart with their axes coinciding. The charges on the two rings are $+ q$ and $- q$. The potential difference between the centres of the two rings is



1) Zero
2) $\frac{Q}{{4\pi {\varepsilon _0}}}\,\left[ {\frac{1}{R} - \frac{1}{{\sqrt {{R^2} + {d^2}} }}} \right]$
3) $QR/4\pi {\varepsilon _0}{d^2}$
4) $\frac{Q}{{2\pi {\varepsilon _0}}}\left[ {\frac{1}{R} - \frac{1}{{\sqrt {{R^2} + {d^2}} }}} \right]$
Solution: Explanation: Explanation
electric-field-potential

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