Categories > Current Electricity > Kirchhoff's Law > When a resistor of $11 \Omega$ is connected in series with an electric cell, the current flowing in it is 0.5 A. Instead, when a resistor of $5 \Omega$ is connected to the same electric cell in series, the current increases by 0.4 A. The internal resistance of the cell is

Current Electricity

Question: When a resistor of $11 \Omega$ is connected in series with an electric cell, the current flowing in it is 0.5 A. Instead, when a resistor of $5 \Omega$ is connected to the same electric cell in series, the current increases by 0.4 A. The internal resistance of the cell is


1) $1.5 \Omega$
2) $2 \Omega$
3) $2.5 \Omega$
4) $3.5 \Omega$
Solution: Explanation: No Explanation
Kirchhoff's Law Cells Internal Resistance

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