Current Electricity

Question: Two batteries of e.m.f. 4V and 8 V with internal resistances $1 \Omega$ and $2 \Omega$ are connected in a circuit with a resistance of $9 \Omega$ as shown in figure. The current and potential difference between the points P and Q are

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1) $\frac{1}{3}A\,\,{\rm{and }}\,3V$
2) $\frac{1}{6}A\,\,{\rm{and}}\,{\rm{ }}4V$
3) $\frac{1}{9}A\,\,{\rm{and}}\,{\rm{ 9}}V$
4) $\frac{1}{2}A\,\,{\rm{and}}\,\,12V$
Solution: Explanation: No Explanation
Kirchhoff's Law Cells Internal Resistance

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