Current Electricity

Question: n identical cells each of e.m.f.E and internal resistance r are connected in series. An external resistance R is connected in series to this combination. The current through R is

1) $\frac{{nE}}{{R + nr}}$

2) $\frac{{nE}}{{nR + r}}$

3) $\frac{E}{{R + nr}}$

4) $\frac{{nE}}{{R + r}}$

Solution:

Explanation: No Explanation

Kirchhoff's Law Cells Internal Resistance

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