Two wires of equal diameters, of resistivities ${\rho _1}$ and ${\rho _2}$ and lengths $l_1$ and $l_2$, respectively, are joined in series. The equivalent resistivity of the combination is

Question

Two wires of equal diameters, of resistivities ${\rho _1}$ and  ${\rho _2}$ and lengths $l_1$ and $l_2$, respectively, are joined in series.  The equivalent resistivity of the combination is

Accepted Answer

$\frac{{{\rho _1}{l_1} + {\rho _2}{l_2}}}{{{l_1} + {l_2}}}$

Answer

$\frac{{{\rho _1}{l_2} + {\rho _2}{l_1}}}{{{l_1} - {l_2}}}$

Answer

$\frac{{{\rho _1}{l_2} + {\rho _2}{l_1}}}{{{l_1} + {l_2}}}$

Answer

$\frac{{{\rho _1}{l_1} - {\rho _2}{l_2}}}{{{l_1} - {l_2}}}$

Current Electricity

Question: Two wires of equal diameters, of resistivities ${\rho _1}$ and ${\rho _2}$ and lengths $l_1$ and $l_2$, respectively, are joined in series. The equivalent resistivity of the combination is

Current Electricity

Question: Two wires of equal diameters, of resistivities ${\rho _1}$ and ${\rho _2}$ and lengths $l_1$ and $l_2$, respectively, are joined in series. The equivalent resistivity of the combination is

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