Current Electricity

Question: Two wires of same metal have the same length but their cross-sections are in the ratio $3:1$. They are joined in series. The resistance of the thicker wire is $10\,\Omega$. The total resistance of the combination will be

1) $40\,\Omega $

2) $\frac{{40}}{3}\Omega $

3) $\frac{5}{2}\Omega $

4) $100\,\Omega $

Solution:

Explanation: No Explanation

Grouping of Resistors Combination of Resistors

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